Khái niệm cốt lõi
This paper proposes an enhancement to Conformal Prediction (CP) by incorporating e-test statistics to introduce a new BB-predictor (bounded from the below predictor), providing a fresh perspective on quantifying uncertainty in machine learning predictions.
Tóm tắt
The paper explores Conformal Prediction (CP), a robust framework for quantifying uncertainty in machine learning predictions without relying on assumptions about the data distribution. The authors introduce an alternative approach to CP by leveraging e-test statistics, which are based on Markov's inequality.
Key highlights:
- CP typically relies on p-values, but the authors venture down a different path using e-test statistics.
- The main theoretical result (Theorem 1) demonstrates that for exchangeable non-negative random variables, the ratio of the last element to the average of all elements has an expectation of 1 and can be effectively constrained using Markov's inequality.
- The authors introduce a new BB-predictor (bounded from the below predictor) that utilizes this property to generate statistically valid prediction regions.
- The paper examines the application of CP and the proposed BB-predictor on the MNIST dataset, comparing the results with the standard Inductive Conformal Prediction approach.
- The authors highlight the importance of non-conformity measures and their role in supervised learning, further reinforcing the concepts discussed.
Thống kê
Ln+1 / ((L1 + ... + Ln + Ln+1) / (n + 1)) >= 1 / (α + (α - 1) / n)
(n + 1)Ln+1 >= (α(n + 1) - 1)(L1 + ... + Ln)
Trích dẫn
"Conformal Prediction (CP) serves as a robust framework that quantifies uncertainty in predictions made by Machine Learning (ML) models."
"The idea behind e-test statistics is very simple and is a straightforward application of Markov's inequality: if E is non-negative random variables with the expectation E(E) ≤1, then P(E ≥1/α) ≤α, for any positive α."
"Suppose L1, . . . , Ln+1 are exchangeable non-negative random variables. Set F = Ln+1 / ((L1 + ... + Lj) / (n + 1)). Then the expectation E(F) = 1 and P{F ≥1/α} ≤α, for any positive α."